sql-server – 模仿group_concat()与GROUP BY结合使用

我有一张像这样的预订表：

booking_id,date,client,sponsor

我正在尝试获得每月摘要：

SELECT 
  MONTH(date) AS M,Sponsor,Client,COUNT(booking_id) AS c
FROM booking
GROUP BY
 M,Client

现在我想知道客户在哪些日期预订.我尝试使用STUFF()(在这篇文章中引用：Simulating group_concat MySQL function in Microsoft SQL Server 2005?)但它与group-by语句冲突.

根据请求提供样本数据.目前我有以下内容：

M       Sponsor     Client  c     
March   AB          y       3
March   FE          x       4
April   AB          x       2

期望的输出：

M       Sponsor     Client  c   dates
March   AB          y       3   12,15,18
March   FE          x       4   16,19,20,21
April   AB          x       2   4,8

数字是天数(例如12月3日,3月15日,3月18日).在mysql中我会使用group_concat(date)来获取最后一列.

答案的大赞誉:-)

解决方法

SELECT [Month] = DATENAME(MONTH,M),c,[dates] = STUFF((SELECT ',' + RTRIM(DATEPART(DAY,[date])) 
    FROM dbo.booking AS b
    WHERE b.Sponsor = x.Sponsor
      AND b.Client = x.Client
      AND b.[date] >= x.M AND b.[date] < DATEADD(MONTH,1,x.M) 
    ORDER BY [date]
    FOR XML PATH('')),2,'')
FROM 
(
  SELECT 
      M = DATEADD(MONTH,DATEDIFF(MONTH,'19000101',[date]),'19000101'),COUNT(booking_id) AS c
    FROM dbo.booking
    GROUP BY DATEADD(MONTH,Client
) AS x
ORDER BY M,Client;

请注意,如果赞助商/客户的组合在同一天有两次预订,则该日期号将在列表中出现两次.

编辑这是我测试的方式：

DECLARE @booking TABLE
( 
  booking_id INT IDENTITY(1,1) PRIMARY KEY,[date] DATE,Sponsor VARCHAR(32),Client VARCHAR(32)
);

INSERT @booking([date],Client) VALUES
('20120312','AB','y'),('20120315',('20120318',('20120316','FE','x'),('20120319',('20120321',('20120320',('20120404',('20120408','x');

SELECT [Month] = DATENAME(MONTH,[date])) 
    FROM @booking AS b
    WHERE b.Sponsor = x.Sponsor
      AND b.Client = x.Client
      AND b.[date] >= x.M AND b.[date] < DATEADD(MONTH,COUNT(booking_id) AS c
    FROM @booking
    GROUP BY DATEADD(MONTH,Client;

结果：

Month   Sponsor Client  c       dates
------- ------- ------- ------- --------------
March   AB      y       3       12,18
March   FE      x       4       16,21
April   AB      x       2       4,8

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